RRB NTPC SAMPLE PAPER - ARITHMETIC - 64

1. Assume that
√13 = 3.605 (approximately)
√130 = 11.40 (approximately)

Find the valueof:
√13 + √1300 +  √0.013

(a) 36,164
(b) 37,304
(c) 36,304
(d) 37,164

2. On simplification of (2.644)² - (2.356)² / 0.288 We get:

(a) 1
(b) 4
(c) 5
(d) 6

3. By how much does √12 + √18 exceed √3 + √2 ?

(a) 2(√3 - √2)
(b) 2(√3 - √2)
(c) √3 + 2 √2
(d) √2 - 4 √3

4. The value of (243)^0.16 × (243)^0.04 is equal to:

(a) 0.16
(b) 3
(c) 1/3
(d) 0.04

5. 1 + 1/2 + 1/4 + 1/7 + 1/14 + 1/128 is equal to :

(a) 2
(b) 2.5
(c) 3
(d) 3.5

Railway Recruitment Board (RRB) NTPC Exams Study Kit

Answer:

1. (c) 2. (c) 3. (c) 4. (b) 5. (a)